The notation for derivative just like a function:
f’(x)
For derivative, there are slashy dot thing is called
a prime. The expresion of it is f prime of x. The other notation is y’ (y
prime), because f(x) and y are interchangeable. It also same meaning with , so the notations of
derivative are:
f’(x) = y’
=
is meaning
It
is the key to understanding derivative:
Derivative is slope of tangent line at point. Then remember that
the slope of a line is
For the derivative we need 2 point:
1. (x,f(x))
(x,f(x)) is same meaning with
(x,y), because y replace by f(x).
2. ((h+x),f(h+x))
h is change in x.
we can slope
of line between 2 points into the slope formula
the slope formula is or
Subtitute the two points (x,f(x)) ,((h+x),f(h+x))
in to the slope formula:
= x is cancelled out by –x, so we find that
The definition of derivative is
f’(x)= we can read it “f prime x is the limit f(x
plus h) minus f(x) all divide by h, h approach zero.
So, f’(x) is the limit of slope, but if we look
closer, we will know that it’s also limit change in values of f(x) over change
in x. It’s also instantaneous rate of change.
Let's do this exercise:
Given: f(x)= 4x²-8x+3
Find: f’(2)
Let’s follow the prosedure to solve
this question:
To slope this question, first thing
we do is subtitute our x in the derivative
definition. In our problem f’(2) is change x by 2. So, subtitute 2 for x in the
derivative definition.
f’(x)= , x=2
f’(2)=
To get f(2), subtitute 2 into the given function
f(2)= 4(2)²-8(2)+3
= 3
So we find x and y
coordinates is (2,3), because f(2)=3
To complete the
formula, we need f(2+h). Then subtitute (2+h) in to the given function
f(2+h)= 4(2+h)²-8(2+h)+3
= 4(4+4h+4h²)-8(2+h)+3
= (16+16h+16h²)-(16 +
8h)+3
= 4 h²+8h+3
To get derivative,
subtitute values of f(2) and f(2+h) in to derivative formula
f’(2)=
=
Remember, we can’t subtitute zero for h
because we get zero in denominator. And remember, if we doing limits, if you
can’t subtitute , try simplifying or factoring.
= h is cancelled out
= 4h+8 subtitute zero in to h
= 8
The solution of f’(2) is 8, so f’(2)= 8 is slope at (2,3).
The
general formula of derivative notation
Find derivative for any value of x on function al lot quicker
Given: f(x)= 4x²-8x+3
replace x by (x+h)
f(x+h)= 4 (x+h) ²-8(x+h)+3
= 4(x²+2xh+h²)-8x-8h+3
= 4 x² + 8xh + 4 h²- 8x-8h +3
Subtitute f(x) and f(x+h) in to derivative formula:
f’(x)=
=
= h is cancelled out
= subtitute zero in to h
= 8x-8
At any value of x the general formula for the derivative f(x)=
4x²-8x+3 is 8x-8
To find the derivative of any value
of x, just subtitute x, for example if x=3
f’(3)= 8(3)-8
= 16.
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